Concrete Washout Containment Volume
Sizes the lined pit or container that catches chute and pump rinse so high-pH slurry never reaches the ground or a storm drain (required by the CGP): required volume = trucks x washout / 7.48 x (1 + freeboard); pit side = sqrt(volume / depth). 20 trucks at 50 gal each is 1,000 gal - 154 cf (5.7 cy), a ~9 ft square pit at 2 ft deep. Built for the whole day's washouts, not one truck; the CGP governs containment.
Formula and source
total_gal = trucks x washout_gal_per_truck; required_cf = total_gal / 7.48052 x (1 + freeboard_pct/100); required_cy = required_cf / 27; pit_side_ft = sqrt(required_cf / pit_depth_ft).
Washout-containment identity by name (volume from trucks x per-truck washout, plus freeboard; pit side from volume / depth); first-principles volume arithmetic.
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