Groove Weld Length for an Applied Load
The inverse of the groove-weld-strength tile: the weld length an applied load needs at a given effective throat, L = load / (stress_ksi x 1000 x throat), with stress_ksi = 0.30 FEXX (ASD) or 0.75 x 0.60 FEXX (LRFD). A 100,000 lb LRFD load on a 0.25 in E70 PJP throat needs about 12.7 in. Round up, split between joint sides, and add for returns and minimum-length rules. AWS D1.1 / AISC 360 §J2; the WPS and engineer of record govern.
Formula and source
required_length = applied_load / (stress_ksi x 1000 x throat), the inverse of capacity = stress_ksi x 1000 x throat x length; stress_ksi = 0.30*FEXX (ASD) or 0.75*0.60*FEXX (LRFD); throat = CJP thinner part thickness or PJP WPS effective throat.
Groove weld (CJP / PJP) shear capacity (AISC 360 Table J2.5 weld-metal shear 0.60*FEXX on the effective throat), solved for the length, per AWS D1.1 Structural Welding Code and AISC 360 §J2, by name.
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