Pipe Insulation Thickness for a Target Heat Loss

The pipe insulation thickness that caps radial heat loss at a target rate per foot.

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Details, formula, and sources

thickness = (od/2) x (exp(2*pi*(k/12)*(hot - amb)/q) - 1). A 2 in pipe at 200 F in 70 F air with k 0.25 held to 40 BTU/hr/ft needs about 0.53 in of insulation. Targets a heat-loss (energy-code / process) budget, not a surface temperature, which is a separate limit. Round up to a stocked wall; conduction only (conservative). ASHRAE / ASTM C335 and the manufacturer govern.

thickness = (OD/2) x (exp(2*pi*k'*(T_hot - T_amb)/q) - 1), the inverse of q = 2*pi*k'*(T_hot - T_amb)/ln(r2/r1), where r1 = OD/2, k' = k_value/12 (BTU/(hr.ft.F)), and q is the target heat loss per foot.

Fourier conduction through a cylindrical shell (public heat-transfer formula), solved for the thickness; insulation k-values per ASHRAE Fundamentals / ASTM C335, by name.

Free principles in published HVAC texts; k-values user-supplied.

Estimate. AHJ and licensed mechanical contractor govern. ACCA Manual J / D / S supersede rules of thumb.

Field names used by the API: od_in, k_value, hot_f, amb_f, target_q_per_ft_btuh, thickness_in, r2_in

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