Transformer Inrush Coordination Point
Why a code-legal primary device still trips on energization.
Example
You enter
- Transformer rating (kVA) 75
- Primary line voltage (V) 480
- Phase 3
- Inrush multiple (x FLA) 12
- Duration (s) 0.1
You get
- Full-load current (FLA) 90.2 A
- Inrush coordination point 1083
Details, formula, and sources
a device meeting the NEC 450.3 percentage limits can still nuisance-trip on the magnetizing inrush. Energized at an unfavorable point on the wave, the core saturates and draws 8-12x FLA (up to ~25x in the first sub-cycle), decaying over a few cycles. FLA = kVA x 1000 / (sqrt(3) x V); inrush point = multiple x FLA at the stated time. A 75 kVA, 480 V transformer draws 90.2 A FLA, so the 12x inrush point is 1,083 A at 0.1 s (and 2,255 A at 0.01 s) -- the primary device's curve must sit RIGHT of that point and LEFT of the damage curve, or it trips every energization. A design aid; the manufacturer's inrush data and a coordination study govern.
FLA = kVA x 1000 / (sqrt(3) x V) three-phase (kVA x 1000 / V single-phase); inrush_point = inrush_multiple x FLA at the stated duration.
Transformer energization-inrush coordination point (IEEE C57.109 through-fault / energization; NEC 450.3 context), first-principles, by name; the manufacturer's inrush data and a coordination study govern.
The FLA and inrush-multiple relations are first-principles; the inrush multiple and duration come from the transformer's energization data and a coordination study.
Estimate. AHJ and licensed professional govern.
Field names used by the API: kva, primary_voltage_v, phase, inrush_multiple, duration_s, fla_a, inrush_point_a
- Inrush multiple commonly 8 to 12x FLA at 0.1 s, up to about 25x in the first sub-cycletransformer energization
- Curve placement the primary device curve must sit right of the inrush point and left of the damage curveIEEE C57.109
- Variability the actual inrush depends on point-on-wave, residual flux, and transformer designmanufacturer data