Orifice Diameter for a Target Flow

The diameter that passes a target flow under a steady head.

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Example

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Checked against published worked examples from: City of Fayetteville, AR (after the Georgia Stormwater Manual).

Details, formula, and sources

ScopeFrom Q = Cd A sqrt(2 g h) solved for A = Q / (Cd sqrt(2 g h)) and d = sqrt(4 A / pi), Cd about 0.6 sharp-edged, head to the orifice center. To release 1.5 cfs under a 4 ft head takes a 5.34 in orifice (0.156 ft^2); because the flow scales with the square root of head, the required area scales as 1/sqrt(h), so a 4x head shrinks the diameter to 0.71x - the sizing side of a detention-outlet or restrictor plate. Free/submerged, steady head, small orifice; the falling-head time-to-drain is separate. A design aid; the engineer of record governs.

Formula or tableA = Q / (Cd sqrt(2 g h)) (g = 32.2 ft/s^2); d = 12 sqrt(4 A / pi) in.

Source and editionThe orifice discharge equation Q = Cd A sqrt(2 g h) solved for the orifice diameter, the inverse of the orifice-discharge tile, a standard hydraulics result, by name.

Free accessThe orifice equation is a public closed-form hydraulics result; the discharge coefficients are in the standard references.

What governsEstimate. AHJ and licensed professional govern.

API field namesq_cfs, h_ft, cd, a_ft2, d_in

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