Tailstock Setover for Taper Turning
The lathe tailstock offset to turn a taper between centers.
Example
You enter
- Overall length between centers OAL (in) 12
- Large diameter D (in) 1.5
- Small diameter d (in) 1
- Length over taper L (in) 8
You get
- Tailstock setover 0.375 in
- Setover per inch of length 0.03125 in/in
Details, formula, and sources
S = OAL x (D - d) / (2 L). The step people miss: the setover scales with the OVERALL length between centers, not the taper length, because the whole part pivots about the headstock center. A 12 in part with a 1.500-to-1.000 in taper over 8 in needs 0.375 in of setover; if the taper ran the full length it would be just (D - d)/2 = 0.250 in. Offset the tailstock away from the tool to put the small end at the tailstock. Shallow tapers only -- the method swings the center holes off axis, so steep tapers want a taper attachment or the compound. A setup aid; check the first part.
S = OAL x (D - d) / (2 L); per-inch setover = (D - d) / (2 L). When L = OAL it reduces to S = (D - d) / 2.
Lathe tailstock setover for taper turning between centers - first-principles as in Machinery's Handbook (Industrial Press), by name; public domain.
Pure geometry, public; the offset comes from the part length and the taper diameters.
Estimate. AHJ and licensed professional govern.
Field names used by the API: overall_length_in, large_dia_in, small_dia_in, taper_length_in, setover_in, per_inch_setover_in
- Overall length OAL is the full length between centers; the setover scales with it, not the taper lengthtailstock-offset geometry
- Shallow tapers the method swings the centers off axis, so it suits shallow tapers; steep tapers need a taper attachment or compoundmachine practice