Pipe Insulation and Jacket Material Takeoff
The mechanical insulator's material list: cut = pipe x (1 + waste) + fittings x allowance; sections = ceil(cut / section length); jacket = pi x insulation OD x cut. 250 ft of 2 in pipe with a dozen ells at 5% waste is 274.5 ft of insulation - 92 three-foot sections and 323 sf of jacket; thicker insulation at a 6 in OD raises the jacket to 431 sf while the section count holds. The OD drives the jacket, the length drives the sections. Distinct from the thermal insulation-thickness.
Formula and source
cut_ft = pipe_ft x (1 + waste_pct/100) + num_fittings x fitting_allow_ft; sections = ceil(cut_ft / section_len_ft); jacket_sf = PI x (insul_od_in/12) x cut_ft.
Mechanical-insulation takeoff identity by name (cut length with fitting allowances; sections and jacket from the cut); first-principles takeoff arithmetic.
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