Punch / Shear Force
Punching force from the cut perimeter (round, rectangular, or entered directly), material thickness, and shear strength.
Example
You enter
- Hole shape round
- Hole diameter (in, round) 0.5
- Material thickness T (in) 0.25
- Shear strength (psi) 50000
You get
- Cut perimeter 1.57080 in
- Punching force 19635
- Force (ton) 9.81748
- Stripping force (est.) 687.2 lb
Checked against published worked examples from: Mate Precision Technologies.
Details, formula, and sources
ScopeF = perimeter x T x shear strength, in pounds and US tons, with an estimated stripping force (first-principles shear).
Formula or tableCut perimeter (pi x D round, 2(a+b) rectangular, or entered); force F = perimeter x T x shear strength; tons = F / 2000; stripping ~= 3.5% of F.
Source and editionPunching force as sheared area times shear strength - first-principles as in Machinery's Handbook (Industrial Press), by name; public domain.
Free accessFirst-principles shear; the shear strength (~0.8 x UTS for mild steel) is user-supplied.
What governsEstimate. AHJ and licensed professional govern.
API field namesshape, diameter_in, thickness_in, shear_strength_psi, perimeter_in, force_lb, force_tons, stripping_lb
- Shear strength the material shear strength (~0.8 x UTS for mild steel) is user-suppliedshear mechanics