Three-Phase Power
kW, kVA, and kVAR from line values and power factor.
Example
You enter
- Line-to-line voltage (V) 480
- Line current (A) 100
- Power factor 0.9
You get
- kVA 83.138
- kW 74.825
- kVAR 36.239
Checked against published worked examples from: U.S. Department of Energy, Motor Challenge.
Details, formula, and sources
Formula or tableS = √3 × V_LL × I (apparent VA); P = S × pf (real W); Q = S × sin(acos(pf)) (reactive VAR).
Source and editionClassical AC power theory; IEEE 141 (Red Book) by name.
Free accessIEEE-USA outreach materials free; IEEE 141 itself is licensed.
What governsEstimate. AHJ and licensed electrician govern. Verify against the NEC edition adopted in your jurisdiction.
API field namesV_LL, I_L, pf, kVA, kW, kVAR
- Balanced load balanced load assumed; per-phase imbalance is not an inputcalculation convention